15c^2-19c+6=

Solution for 15c^2-19c+6= equation:

Simplifying
15c2 + -19c + 6 = 0

Reorder the terms:
6 + -19c + 15c2 = 0

Solving
6 + -19c + 15c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(3 + -5c)(2 + -3c) = 0

Subproblem 1
Set the factor '(3 + -5c)' equal to zero and attempt to solve:

Simplifying
3 + -5c = 0

Solving
3 + -5c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -5c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -5c = 0 + -3
-5c = 0 + -3

Combine like terms: 0 + -3 = -3
-5c = -3

Divide each side by '-5'.
c = 0.6

Simplifying
c = 0.6
Subproblem 2
Set the factor '(2 + -3c)' equal to zero and attempt to solve:

Simplifying
2 + -3c = 0

Solving
2 + -3c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -3c = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -3c = 0 + -2
-3c = 0 + -2

Combine like terms: 0 + -2 = -2
-3c = -2

Divide each side by '-3'.
c = 0.6666666667

Simplifying
c = 0.6666666667
Solution
c = {0.6, 0.6666666667}